1.5 gram of ethane on complete combustion give 4.4 gram of co2 and 2.7 gram of H2O so that the results are in accordance with the law of conservation of mass.
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5.6 gram oxygen makes this equation accordingly
tusharjalan0:
Please explain in detail
Please answer fast
by this process The first step here is to determine the mass of C in CO2 and the mass of H in H2O. This is done by dividing the atomic mass by the molecular mass and then multiplying by the mass of compound produced.
For C:
(12.011 g / 44.009 g) x 4.40 g = 1.1999 g
For H:
(1.0079 x 2 / 18.0148 g) x 2.70 g = 0.3021 g
The next step is to convert these masses into moles. This is done by dividing the mass by the relative atomic mass of the element:
For C:
(12.011 g / 44.009 g) x 4.40 g = 1.1999 g
For H:
(1.0079 x 2 / 18.0148 g) x 2.70 g = 0.3021 g
The next step is to convert these masses into moles. This is done by dividing the mass by the relative atomic mass of the element:
C: 1.1999 g / 12.011 g mol-1 = 0.0999 mol
H: 0.3021 g / 1.0079 g mol-1 = 0.2997 mol
The final step is to divide each of these two values by the smallest number, in this case this is the number of moles of carbon:
C: 0.0999 mol / 0.0999 mol = 1
H: 0.2997 mol / 0.0999 mol = 3
We therefore have a ratio of 1 carbon atom to 3 hydrogen atoms, thus the empirical formula for this hydrocarbon is CH3.
H: 0.3021 g / 1.0079 g mol-1 = 0.2997 mol
The final step is to divide each of these two values by the smallest number, in this case this is the number of moles of carbon:
C: 0.0999 mol / 0.0999 mol = 1
H: 0.2997 mol / 0.0999 mol = 3
We therefore have a ratio of 1 carbon atom to 3 hydrogen atoms, thus the empirical formula for this hydrocarbon is CH3.
So what?
this is the process
We dont have to find empirical formula
We have to prove it
Answered by
2
Answer:
Hydrocarbon undergoes combustion to form carbondioxide and water.
molecular mass of carbondioxide = 44gm
molecular mass of water = 18 gm
mass of Carbon in 4.4 gm of carbondioxide = (12/44) * 4.4 = 1.2 gm
mass of Hydrogen in 2.7 gm of water = (2/18)*2.7 = 0.3 gm
So,
Total mass of Hydrogen and Carbon = (1.2 +.3)gm = 1.5 gm
This is the same mass before combustion.
Explanation:
So , the results are accordance with the law of conservation of mass.
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