Two train each 500 m long, are running in opposite directions on parallel tracks. if their speeds are 45 km/hr. and 30 km/hr. respectively, the time taken by the slower train to pass the driver of the faster one is
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Relative speed == (45 + 30) km/hr=75 x5m/sec18=125m/sec.6
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
Required time =500 x6= 24 sec.125
Answered by
8
relative speed = 45+30= 75km/hr
in seconds= 75x5/18 = 125/6 seconds
distance covered = Length of the slower train.
= 500m
Required time =500/125×6 = 24 seconds
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in seconds= 75x5/18 = 125/6 seconds
distance covered = Length of the slower train.
= 500m
Required time =500/125×6 = 24 seconds
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