Two train each 50m long travelling in opposite direction with velocity 10mper s the time of crossing is
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The velocity of 2nd train relative to first train is 15-(-10)=25m/s, when we say relative to first train then first train has to be considered stationary. With this picture second train has to travel 100 m with relative velocity of 25m/s. So, it will take 100/25=4s.
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