Two train of length 110 metres and 200 metres respectively are running in same direction with the speed of 20 km/ hr and 16km/hr respectively . In what will they cross each other?
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Answer:
let the length of 1st train L1= 120m
length of 2nd train L2= 80m
speed of 1st train S1=42 km/hr
speed of 2nd train S2 = 30 km/hr
now formula is
speed= distance/ time
so,
S1 + S2 = (L1 + L2)/ time
(42 + 30) km/hr = (120+80) m/ time
72 km/hr = 200 m/ time
now convert the speed from km/hr to m/s by multipying 5/18
72*5/18 = 200/ time
20 m/s = 200 m/ time
time= 200/ 20
time = 10 seconds
so the train will cross each other in 10 seconds
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