Two train one of length 100 m and another of
length 125 m, are moving in mutually opposite
directions along parallel lines, meet each other,
each with speed 10 m/s. If their acceleration are
2
0.3 ms
and
2
0.2 ms
respectively, then the time
they take to pass each other will be
(a) 5 s (b) 10 s (c) 15 s (d) 20 s
Answers
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Question :-
⇒ Two train one of length 100 m and another of length 125 m, are moving in mutually opposite directions along parallel lines, meet each other, each with speed 10 m/s. If their acceleration are 20.3 ms ^2 and 0.2 ms ^2 respectively, then the time they take to pass each other will be ?
Answer:-
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Thank you
ravindrabansod26:
of my answers help full
⇒ Two train one of length 100 m and another of length 125 m, are moving in mutually opposite directions along parallel lines, meet each other, each with speed 10 m/s.
⇒ S = ( 100 + 125 )mS=(100+125)m
⇒ S = 225mS=225m
⇒ Area = 0.3 + 0.2 = 0.5Area=0.3+0.2=0.5
⇒ V_real = 20ms^{-1}Vreal=20ms−1
⇒ S = ut + \frac{1}{2} at^2S=ut+21at2
⇒ 225 = 20t + \frac{1}{4} t^2225=20t+41t2
⇒ 900 = 80t + t^2900=80t+t2
⇒ t^2 + 80t - 900 = 0t2+80t−900=0
⇒ t = 10st=10s
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