Math, asked by prashishbansod, 4 months ago

Two train one of length 100 m and another of

length 125 m, are moving in mutually opposite

directions along parallel lines, meet each other,

each with speed 10 m/s. If their acceleration are

2

0.3 ms

and

2

0.2 ms

respectively, then the time

they take to pass each other will be

(a) 5 s (b) 10 s (c) 15 s (d) 20 s​

Answers

Answered by ravindrabansod26
28

Question :-

⇒ Two train one of length 100 m and another of  length 125 m, are moving in mutually opposite  directions along parallel lines, meet each other,  each with speed 10 m/s. If their acceleration are  20.3 ms ^2 and  0.2 ms ^2 respectively, then the time  they take to pass each other will be ?

Answer:-

S = ( 100 + 125 )m

S = 225m

Area = 0.3 + 0.2 = 0.5

Area = \frac{1}{2} m/s^2

V_real = 20ms^{-1}

S = ut + \frac{1}{2} at^2

225 = 20t + \frac{1}{4} t^2

900 = 80t + t^2

t^2 + 80t - 900 = 0

t  = 10s

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Thank you


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ravindrabansod26: Question :-

⇒ Two train one of length 100 m and another of  length 125 m, are moving in mutually opposite  directions along parallel lines, meet each other,  each with speed 10 m/s.
ravindrabansod26: If their acceleration are  20.3 ms ^2 and  0.2
ravindrabansod26: ms
ravindrabansod26: Answer:-

⇒ S = ( 100 + 125 )mS=(100+125)m
⇒ S = 225mS=225m
⇒ Area = 0.3 + 0.2 = 0.5Area=0.3+0.2=0.5
ravindrabansod26: ⇒ Area = \frac{1}{2} m/s^2Area=21​m/s2
⇒ V_real = 20ms^{-1}Vr​eal=20ms−1
⇒ S = ut + \frac{1}{2} at^2S=ut+21​at2
⇒ 225 = 20t + \frac{1}{4} t^2225=20t+41​t2
⇒ 900 = 80t + t^2900=80t+t2
⇒ t^2 + 80t - 900 = 0t2+80t−900=0
⇒ t = 10st=10s
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