Question

Two train travelling at 90 m/s and other travelling at 120 m/s are moving towards each other on the same track . when they are 11 km apart both drivers simultaneously apply brakes .if the brakes deaccelerate each train at the rate of 3m/s2 , then the distance travelled by the first train is

Answer 1

u = Initial velocity
v = final velocity
a = acceleration
s = distance covered

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Answer 2

Answer:

The distance traveled by the first train is 1350 m.

Explanation:

Given that,

Speed of first train = 90 m/s

Speed of second train = 120 m/s

Distance d = 11 km

Acceleration = 3 m/s

Both trains are moving towards each other on the same track.

We need to calculate the distance traveled by train A when the breaks applied.

Using equation of motion

$v^2-u^2=2as$

Where, v = final velocity

u = initial velocity

s = distance

a = acceleration due to gravity

$0-8100=2\times(-3)\times s$

$s=\dfrac{8100}{6}$

$s=1350\ m$

Hence, The distance traveled by the first train is 1350 m.