Question

Two trains 100 m and 80 m long, respectively are running in opposite directions. Trains A running with constant velocity 10 m/s and train B, start from rest and running with uniform acceleration 5 m/s? If the initial separation between two trains is 80 m Then after what time they meet each other (In second)​

Answer 1

Answer:

u1=50m/s

u2=0

s1=u×t

a2=10m/s2

s1=50t

s2=u2t+21a2t2

s2=0+21×10×t2=5t2

s1−s2=125⇒50t−5t2=125

⇒t2−10t+25=0⇒t=5