Question

two trains 110m and 100m long are running on parallel trackin the

Answer 1

Answer:

44 seconds

Step-by-step explanation:

In the question, the position of the trains at t0 is not given. So I will take t0 when the faster train’s head is at the tip of the slower trains tail. And assuming that the speeds mentioned are respective and the faster train will cross the second.

|——————————-|120m (54 kmph)

………………………………|———————-|100m (72 kmph)

So the total distance the faster train needs to travel to cross the slower train is 220m

………………………|——————————-|120m (54 kmph)

|———————-|100m (72 kmph)

And the relative speed is S1 - S2 = 72–54 = 18 kmph or in mps 18*5/18 = 5 ms/s

So time taken to travel the distance = distance/speed = 220/5 = 44 seconds.

I hope this is helpful  for u .