Two trains are moving in the opposite direction and their speeds are in the ratio of 4:13.the first trsin passes a standing man in 13.25 second and another in 9 second. the time taken by trains to cross each other is?
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Answered by
3
Distance travelled by Ist train=13.25×4
=53m/sec
Respectively,2nd train=9×13
=117m/sec
Total distance= 117m+53m
= 170m
Total speed= 13+4 = 17sec
Time taken = 170/17 = 10 sec .ans
=53m/sec
Respectively,2nd train=9×13
=117m/sec
Total distance= 117m+53m
= 170m
Total speed= 13+4 = 17sec
Time taken = 170/17 = 10 sec .ans
ashaq1:
wrong
How
17 sec , it is total time not total speed
Answered by
4
Solution:-
given by:-
》the ratio = 4:13
》let -->the both train speed is 4xm/s and 13xm/s
》first train length is = 4x×13.25 = 53xmtr
》2nd train length is = 13x×9 = 117xmtr
》bcoz trains speed is opposite direction
then total speed = 4x+13x =17xm/s
》total length = 117x+53x= 170xmtr
》 the time taken by trains to cross each other is:
》 time = length/speed
》 time = 170x/17x
》 ( time = 10second ) ans
☆ i hope is help☆
given by:-
》the ratio = 4:13
》let -->the both train speed is 4xm/s and 13xm/s
》first train length is = 4x×13.25 = 53xmtr
》2nd train length is = 13x×9 = 117xmtr
》bcoz trains speed is opposite direction
then total speed = 4x+13x =17xm/s
》total length = 117x+53x= 170xmtr
》 the time taken by trains to cross each other is:
》 time = length/speed
》 time = 170x/17x
》 ( time = 10second ) ans
☆ i hope is help☆
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