Question

Two trains are moving in the opposite directions at speed of 43 km/h and 51 km/h respectively. the time taken by the slower train to cross a man sitting in the faster train is 9 seconds. what is the length (in metres) of the slower train?

Answer 1

the velocity of slow train=43km/h......1st
the velocity of faster train=51km/h.....2n
when the two heads of each train meets at a common point the total speed of slow train is equal to 43+51km/h=94mk/h=26.11m/s
therefore distance of slow train=speed ×time
=26.11×9
=234.99metres

Answer 2

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