Two trains are travelling in opposite direction at the speed of 70 km per hour and 100 km per hour their lengths are 700 M and 575 M respectively the time taken by slower train to cross the faster train is ?
Answers
Answer:
Step-by-step explanation:
Let length of faster train and slower train be x and y respectively
When they travel in opposite direction, trains cross each other in 5 sec
Relative speed = 60+50 =110 km/hr =
110
×
5
18
=
550
18
m/s
Distance travelled = x+y
Time taken to cross each other = 5 s
(x+y) =
550
×
5
18
=
1375
9
---(1)
When they travel in same direction, passenger sitting in the faster moving train would have overtaken the other train in 18 sec
Relative speed = 60-50 =10 km/hr =
10
×
5
18
=
50
18
m/s
Since the observation given is of a passenger sitting in faster train, distance travelled is equal to length of the slower train.
i.e, distance travelled = y m
Time taken for overtaking = 18 s
y =
50
18
×
18
= 50 m
From(1), x + 50 =
1375
9
x =
1375
9
−
50
=
925
9
= 102.78 m
Answer:
Step-by-step explanation:Let length of faster train and slower train be x and y respectively
When they travel in opposite direction, trains cross each other in 5 sec
Relative speed = 60+50 =110 km/hr =
110
×
5
18
=
550
18
m/s
Distance travelled = x+y
Time taken to cross each other = 5 s
(x+y) =
550
×
5
18
=
1375
9
---(1)
When they travel in same direction, passenger sitting in the faster moving train would have overtaken the other train in 18 sec
Relative speed = 60-50 =10 km/hr =
10
×
5
18
=
50
18
m/s
Since the observation given is of a passenger sitting in faster train, distance travelled is equal to length of the slower train.
i.e, distance travelled = y m
Time taken for overtaking = 18 s
y =
50
18
×
18
= 50 m
From(1), x + 50 =
1375
9
x =
1375
9
−
50
=
925
9
= 102.78 m