Question

Two trains, each having a speed of 30 km/h, are headed at
each other on the same straight track. A bird that can fly 60 km/h
flies off the front of one train when they are 60 km apart and heads
directly for the other train. On reaching the other train, the bird
flies directly back to the first train, and so forth. (We have no idea
why a bird would behave in this way.) What is the total distance the
bird travels before the trains collide?

Answer 1

Answer:

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Answer 2

60 killometer.

Explanation:

Given:

Speed of train: 30 km/hr

Speed of bird : 60 km/hr

Distance between two train : to be found?

Solution:

As given that both the train are running on same speed which is 30 km/hr so both the train will expected to met or collide at 30 km and the time taken in this is :

     t =$\frac{\text {distance traveled}}{\text {speed of the train}}$ = $\frac{30 km}{30km/hr}$ = 1.00 hr

so, the birds that flying 60 km/hr will travel would be before the train colloid is :

     D= time taken × speed of bird

       = 1 × 60 = 60 km