Physics, asked by Sonamsinha6887, 9 months ago

Two trains move in the same direction at 50 kmph and 32kmph respectively a man in the slower train observes

Answers

Answered by RAJNEESH132
0

We have,

speed of faster train = 50kmph

speed of slower train = 32kmph

relative speed = speed of faster train - speed of slower train

= 50kmph - 32kmph

= 18kmph

= 18 × 1000 / 3600 [conversion of kmph to m/s]

= 5m/s

now length of faster train = relative speed x time elasped

= 5m/s × 15s

= 5m × 5

= 75m

hence the length of faster train = 75m

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