Two trains move in the same direction at 50 kmph and 32kmph respectively a man in the slower train observes
Answers
Answered by
0
We have,
speed of faster train = 50kmph
speed of slower train = 32kmph
relative speed = speed of faster train - speed of slower train
= 50kmph - 32kmph
= 18kmph
= 18 × 1000 / 3600 [conversion of kmph to m/s]
= 5m/s
now length of faster train = relative speed x time elasped
= 5m/s × 15s
= 5m × 5
= 75m
hence the length of faster train = 75m
Similar questions
Computer Science,
6 months ago
Math,
6 months ago
Physics,
1 year ago
Physics,
1 year ago
Social Sciences,
1 year ago
Chemistry,
1 year ago
Math,
1 year ago