Two trains R and S start from rest simultaneously from stations A and B facing
each other with accelerations 0.5 m/s2and 2/3 m/s2reaching their maximum speeds
of 90 kmph and 72 kmph respectively. If they cross each other midway between
the stations, find the distance between the stations and the time taken by each
other.
Answers
Answered by
1
for train R:
a=0.5 m/s^2
v=90*5/18=25m/s
u=0 m/s
time taken to reach station B:
v=u+at
25=0+0.5t
t=25/0.5=50 s
S=ut+1/2at^2
S=1/2*0.5*50^2=625 m
For train S:
a=2/3 m/s^2
v=72*5/18=20 m/s
u=0 m/s
time taken to reach station A:
v=u+at
20=0+2/3t
t=30 s
S=ut+1/2at^2
S= 1/2*2/3*30^2=300 m
Distance between the stations = 625 -300=325 m
Time taken by train R = 50 sec
Time taken by train S =30 sec
Similar questions
Physics,
6 months ago
English,
6 months ago
Physics,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago