Two trains travelling at 48kmph completely crosses another train having half it's length and travelling in opposite direction at 42kmph,in 12 seconds. It also passes a railway platform in 45 seconds. Find the length of the platform?
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Answer:
Let the length of the first train be x metres.
Then, the length of the second train is (
2
x
) metres.
Relative speed =(48+42)kmph=(90×
18
5
)m/sec=25m/sec
∴
25
[x+(x/2)]
=12 or
2
3x
=300 or x=200
∴ Length of first train = 200 m
Let the length of platform be y metres.
Speed of the first train =(45×
18
5
)m/sec=
3
40
m/sec
∴(200+y)×
40
3
=45
⇒600+3y=1800
⇒y=400m
Explanation:
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