Two trains X and Y start at the same time in the opposite direction from two points P and Q and arrive at their destinations 36 and 25 hours respectively after their meeting each other. At what speed does the second train Y travel if the first train travels at 80 km/h.?
koi h ❤☺✌foĺlow me
Answers
Answer:
Let speed of Train B = x
120/x= √(9/16)
=> x = 4 x 120/3 = 160 km/hr
Note : This can be solved without using this formula by using fundamentals of Time, Speed & Distance.
Step-by-step explanation:
Derivation of formula :
Let x be the total distance and t be the time at which the two trains meet.
Let s1, s2 are speeds of train A, train B respectively and a & b are the times at which they reach the destination after they meet.
x = t(s1 + s2) ...(1)
x = (t + a)s1 ...(2)
x = (t + b)s2 ...(3)
Solving (1), (2) & (3)
t = √(a*b)
=> Time to meet is the Geometric Mean of individual time after meeting.
=> s1/s2 = √(b/a)
☺hope that's help you
Answer:
Let speed of Train B = x
120/x= √(9/16)
=> x = 4 x 120/3 = 160 km/hr
Note : This can be solved without using this formula by using fundamentals of Time, Speed & Distance.
Derivation of formula :
Let x be the total distance and t be the time at which the two trains meet.
Let s1, s2 are speeds of train A, train B respectively and a & b are the times at which they reach the destination after they meet.
x = t(s1 + s2) ...(1)
x = (t + a)s1 ...(2)
x = (t + b)s2 ...(3)
Solving (1), (2) & (3)
t = √(a*b)
=> Time to meet is the Geometric Mean of individual time after meeting.
=> s1/s2 = √(b/a)
hope this will helps you❤
btw in which standard ?..