Two tree are at distance of 3.14m from each other. what should the maximum distance of an observer from tree to seen them separetly
Answers
Answered by
5
Answer:
0.99m to look apart
Explanation:
According to research on human vision, the limit of resolution of human eye is (1 /60)∘
In order for the trees to be seen separately, this would be possible when
θ > (1 / 60)∘
Simplifying the above,
d / x > (1/60) × π / 180
d > (1/60) × π / 180 * x
d > 3.14× 3.14 × 10^3 / 60 × 180
d > 0.99m
Answered by
0
The maximum distance of the observer from the tree is 1.813 m
Explanation:
Given data:
- T1.T2 = 3.14 m
- T1 x M = M x T2 = 1.57 m
- Tan [ θ / 2] = T1 x M / M x V = [ 1.57 / x ]
- Tan [ θ / 2 ] = [ 1.57 / x ]
The vision will be lost by the viewer if the value of tan 60° is less.
tan [60°] < 1.57 / x
√ 3 < 1.57 / x
x = 1.57 / 3 m
VT1 = V T2 = √ (1.57 / √ 3 )^2 + ( 1.57)^2 m
VT1 = V T2 = 1.57 x 2 / √ 3
VT1 = V T2 = 1.57 x 2 / 1.732
VT1 = V T2 = 1.813 m
Hence the maximum distance of the observer from the tree is 1.813 m
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