Question

Two triangles are similar and the ratio of the pair of corresponding sides is 2:3 . If one of the sides of the smaller triangle is 4 cm , then what will be the length of its corresponding side of the larger triangle? please reply fast its very urgent​

Answer 1

Answer:

6 cm .

Step-by-step explanation:

Given ;

Two triangles are similar .

The ratio of the pair of corresponding sides is 2 : 3 .

Let Δ ABC and Δ PQR are similar  .

Then ,

$\displaystyle{\frac{\Delta ABC}{\Delta PQR}=\dfrac{AB}{PQ}=\dfrac{BC}{QR}=\dfrac{AC}{PR}}$

Let say AB is given side of 4 cm .  

$\displaystyle{\dfrac{AB}{PQ}=\dfrac{BC}{QR}}\\\\\\\displaystyle{\dfrac{4}{PQ}=\dfrac{2}{3}}\\\\\\\displaystyle{\dfrac{2}{PQ}=\dfrac{1}{3}}\\\\\\\displaystyle{PQ=6 \ cm}$

Thus corresponding side is of 6 cm .

Hence we get answer .

Answer 2

Answer :

The length of its corresponding side of the larger triangle - 6cm.

Step-by-step explanation:

Given that :

The ratio of the pair of corresponding sides is 2 : 3.

Two triangles are similar.

One of the sides of the smaller triangle is 4cm.

To Find :

The length of its corresponding side of the larger triangle.

Solution :

★ Consider the -

Δ ABC and Δ XYZ are similar.

{ Given that the two triangles are similar. }

So,

$\star\;\sf \dfrac{Area\Delta ABC}{Area\Delta XYZ}=\dfrac{AB}{XY}=\dfrac{BC}{YZ}=\dfrac{AC}{XZ}}$

{ As, given One of the sides of the smaller triangle is 4cm. }

So,

Assume that AB is given side of 4 cm,

$\sf\\\implies \dfrac{AB}{XY}=\dfrac{BC}{YZ}}\\ \\ \\ \sf \implies \dfrac{4}{XY}=\dfrac{2}{3}}\\ \\ \\ \sf\implies\dfrac{2}{XY}=\dfrac{1}{3}}\\ \\ \\ \sf \implies{XY=6\;cm}$

∴ Corresponding side is of 6 cm.