Question

Two triangles have equal areas. Their bases are in ratio 1:3, find the ratio of their heights.​

Answer 1

Let the ratio be x.
Base of frst triangle= x
Base of sec triangle= 3x
Atq
1/2*x*h of frst triangle=1/2*3x*h of sec triangle
=> x*h/2=3x*h/2
=> x*h of frst tri/3x*h of sec tri=2/2
=> h of frst tri/ 3h of sec tri= 1

Their ratio is 1:3........

Don’t ask me how....it’s bc of the h having literally no value so I just did that. And i have a feeling it’s ryt.