Two triangles have the same height. The base of one triangle is twice as long as the other. What is the difference in their areas?
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Question 221992: two triangles have the same height, the base of one triangle is twice as long as the other, how do the two areas compare?
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The area of a triangle is one-half the base times the height, so if the heights are the same, doubling the length of the base doubles the area.
John
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hey buddy (^o^)
here,
let base of triangle be b and other be B
so, B = 2b (given)
difference in area of both triangle will be,
= 1/2x B x h - 1/2 x b x h
= 1/2 x 2b x h - 1/2 x b x h
= bh - 1/2 bh
= 1/2 x b x h
plz check the answer B-)
HOPE THIS HELPS ;-)
here,
let base of triangle be b and other be B
so, B = 2b (given)
difference in area of both triangle will be,
= 1/2x B x h - 1/2 x b x h
= 1/2 x 2b x h - 1/2 x b x h
= bh - 1/2 bh
= 1/2 x b x h
plz check the answer B-)
HOPE THIS HELPS ;-)
dayaryandj:
What is the outcome
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