Question

two triangles XYZ and PQR are similar and ar (∆XYZ)=4ar(∆PQR).if YZ =12cm find QR a)6cm b)8cm c)4cm d)3cm​

Answer 1

Step-by-step explanation:

as both the triangles are similar

area of triangle xyz is 1/2*xy*yz*siny

are of triangle pqr is 1/2*pq*qr*sinq

by similar triangle property xy/pq=yz/pr=xz/pr=k (let)

since area of triangle xyz=4 times that of pqr

so k2 =4 so k=2

so 12/qr=2 so qr=6