Question

Two triangular pieces ABC and BCD of paper are joined together form a big triangle ABD as shown
in the adjoining figure. Find the area of triangle ABD.
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Answer 1

Given:-

Base=>AC+CD

=>10cm+8cm

=18cm.

Height:-(displacement between AD and point B)

=5.5 cm

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Formula:-

Area of Triangle=1/2*base*height

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Area of Triangle ABD:-

⚫1/2* base *height

⚫1/2 *18*5.5

⚫1/2 *18*5.5

⚫0.5*18.5*5.5

⚫9*5.5

⚫49.5 cm2

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Answer:-

$49.5 \: \: {cm}^{2}$

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POINTS TO REMEMBER:-

You can solve this question from Another Method also......

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By this Formula Area of ABC + Area of BCD

Height of both became same....

(Given)

Base of ABC=10 cm

Base of BCD=8 cm

Area=>(1/2 * 5.5* 10)+(1/2*5.5*8)

=>27.5+22

=>49.5 cm2

Answer 2

there are two types of answer i mean two methods...hope it helps you