Question

Two tubes of different area of cross section filled with a liquid are connected. The area of
cross section of small pipe is 1 m2
and that of the large one is 2m2
. Calculate the pressure
experienced on the large piston if a force of 10 N is applied on the small piston.

Answer 1

Given:-

$\text{cross-sectional area of smaller pipe, }a_{1}=1m^{2}\\\\\text{cross-sectional area of larger pipe, }a_{2}=2m^{2}\\\\\text{Force applied on smaller piston, }F_{1}=10N$

To Find:-

Pressure experienced on the larger piston.

Explanation:-

$\text{Pressure on the fluid due to force on the smaller piston, }P=\dfrac{F_{1}}{a_{1}}=\dfrac{10}{1}=10N/m^{2}$

According to Pascal's law, pressure at every point in a static fluid is same.

Therefore, pressure experienced on the larger piston=pressure on the smaller piston=$10N/m^{2}$

Answer 2

Answer:

Given

\begin{gathered}\text{cross-sectional area of smaller pipe, }a_{1}=1m^{2}\\\\\text{cross-sectional area of larger pipe, }a_{2}=2m^{2}\\\\\text{Force applied on smaller piston, }F_{1}=10N\end{gathered}

cross-sectional area of smaller pipe, a

1

=1m

2

cross-sectional area of larger pipe, a

2

=2m

2

Force applied on smaller piston, F

1

=10N

To Find:-

Pressure experienced on the larger piston.

Explanation:-

\text{Pressure on the fluid due to force on the smaller piston, }P=\dfrac{F_{1}}{a_{1}}=\dfrac{10}{1}=10N/m^{2}Pressure on the fluid due to force on the smaller piston, P=

a

1

F

1

=

1

10

=10N/m

2

According to Pascal's law, pressure at every point in a static fluid is same.

Therefore, pressure experienced on the larger piston=pressure on the smaller piston=10N/m^{2}10N/m

2