Question

Two tug of war teams are on opposite sides of a rope. Team A applies a force of 1,200 N to the right, Team B applies a force of 900 N to the left. What is the net force applied to the rope?

Answer 1

Answer:

As the rope is in equilibrium; F1=F2=1000N so tension in the rope is also equal to 1000N

Explanation:While many people would like to simply add the forces from each end to get a total force, this is fundamentally incorrect.

This is an application of Newton's Third Law: "For every action there is an equal and opposite reaction."

The rope is balanced i.e it is not in motion which means that the net force is 0. If we consider first force as the action and second force as the reaction so tension will be equal to the second force (1000N) in order to make the net force zero (i.e T-F=0)…… If the tension be 2000N (by simply adding the 2 forces) then net force will be 1000N (i.e T-F=1000N) which means the rope is in motion and not in equillibrium and thus we can conclude that the tension in rope should be same as two forces i.e 1000N for the rope to be in equillibrium.

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