Question

Two tungsten bulbs of power 50 W and 60 W work on 220 V
potential difference. If they are connected in parallel, how much
current will flow in the main conductor ?​

Answer 1

Answer

0.5 A (Refer to the attachment)

Explanation

Given

potential difference = 220V

let the power on bulb 1 and bulb 2 be 50W and 60W respectively

We know that

power = Potential difference × current

or, P = V × I

Power on bulb 1 = 50W

=> V × I = 50

=> 220 × I = 50

=> I = 50/220

=> I = 5/22

Power on bulb 2 = 60W

=> V × I = 60

=> 220 × I = 60

=> I = 60/220

=> I = 6/22

In parallel combination, the sum of the currents through each path is equal to the total current that flows from the source

So, Total current = 5/22 + 6/22

=> 11/22 A Or 0.5A

Therefore, 0.5 Ampere current is flowing through the main conductor