Two tungsten bulbs of wattage 100W and 60W power work on 220V potential difference. If they are connected in parallel how much current will flow in the main conductor?
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we know that
Power(P) =Voltage(V) ×Current(I)
so,
I=P/V
Here I1 =100/220 ,n I2 = 60/220
Since, these are in parallel the voltage is the same over both bulbs and there is only a resistance
so, we have
I total= 160/220 =0.728A
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