Question

Two tuning fork of frequencies 710 cps are sounded together ,the No. Of beats produce in 5 sec is?

Answer 1

Answer:

As per the problem, the frequency of beats is ∣ν

1

−ν

2

∣=4

where, ν

1

and ν

2

are the frequencies of given tuning forks.

Hence, the frequency of second tuning fork is either 4 Hz more i.e. 254 Hz or

4 Hz less i.e. 246 Hz than the first one. Now, the first tuning fork is waxed this will reduce its frequency, hence the frequency of beats is now

ν

1

′

−ν

2

=6

Since, decrease in frequency of first tuning fork increases the frequency of

beats(by 2) hence, ν

1

′

=248Hz and therefore for beat frequency 6

Hz, ν

2

=254Hz