Question

two tunning fork of frequencies 340hz 360hz produce sound wave of wavwlength differing by 6cm in medium find velocity of sound in medium?



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Answer 1

this should be the answer

Answer 2

Given that,

Frequency of tuning fork 1, $f_1=340\ Hz$

Frequency of tuning fork 2, $f_2=360\ Hz$

They produce sound wave of wavelength differing by 6 cm.

To find,

The velocity of sound in medium.

Solution,

According to question,

$\lambda_1-\lambda_2=0.06$

Since, $\lambda=\dfrac{v}{f}$

So,

$\dfrac{v}{f_1}-\dfrac{v}{f_2}=0.06\\\\v(\dfrac{1}{f_1}-\dfrac{1}{f_2})=0.06\\\\v=\dfrac{0.06}{(\dfrac{1}{f_1}-\dfrac{1}{f_2})}\\\\v=\dfrac{0.06}{(\dfrac{1}{340}-\dfrac{1}{360})}\\\\v=367.2\ m/s$

So, the velocity of sound in medium is 367.2 m/s.

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