Math, asked by krishbolkuntwar, 2 months ago

Two types of chocolates are available in packets having 10 and 12 chocolates respectively. Find the minimum number of packets to be bought so as to get respectively. Find the minimum number of packets to be baught so as to get equal number of chocolates of both the types. ​

Answers

Answered by Neeruja
4

Step-by-step explanation:

Given, two brands of chocolates are available in pack of 24 and 15 respectively.

We need to buy an equal number of chocolates of both kinds.

For this we find the LCM of 24 and 15

Now,

24=2

3

×3

15=3×5

LCM(24,15)=2

3

×3×5=120

Now,

the number of boxes of pack of 24 =

24

120

=5

and the number of boxes of pack of 15 =

15

120

=8

option B is correct.

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Answered by sumanshinde1982
0

Answer:

50+10=60.

6*10=60 6packets of 10 chocolates and 5packets of 12 chocolate

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