Question

two un equal angels of a parrallelogram are in a ratio 2 ratio 3. find all its angles in degrees​

Answer 1

Answer:

Given that,

Two unequal angles of a parallelogram are in the ratio 2:3.

To find,

All its angles in degrees.

Solution,

Let angle A is 2x and angle B is 3x

We know that the sum of co-interior angles are supplementary.

So,

\begin{gathered}\angle A+\angle B=180^{\circ}\\\\2x+3x=180\\\\5x=180\\\\x=36^{\circ}\end{gathered}

∠A+∠B=180

∘

2x+3x=180

5x=180

x=36

∘

It means that, \angle A=2x=2(36)=72^{\circ}∠A=2x=2(36)=72

∘

and

\angle B=3x=3(36)=108^{\circ}∠B=3x=3(36)=108

∘

Also, the opposite angles of a parallogram are equal

So,

\begin{gathered}\angle A=\angle C=72^{\circ}\\\\\angle B=\angle D = 108^{\circ}\end{gathered}

∠A=∠C=72

∘

∠B=∠D=108

∘

Hence, this is the required solution.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

sum of all angles of a parallelogram is equal to 360 degree so

$let \: the \: angles \: be \: 2x \: and \: 3x \\ \\ so \: 2x + 3x + 2x + 3x = 360 \\ \\ \\ 10x = 360 \\ \\ x = 36$

so the angles are 36into 2 it mean 72 degree and 36 into 3 it mean 108degree