TWO UNBAISED DICE ARE ROLLED.FIND THE PROBABILITY OF GETTING SUM AS A PRIME NUMBER
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total no of possible events=36
sum as prime number=
(1,1),(1,2),(1,4),(1,6),(6,1),(4,1)(2,1)(2,3),(5,2),(2,5),(3,4),(4,3),(3,2),(6,5),(5,6)
=15
therefore
P(E)=15/36
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