Question

two unbiased coins are tossed simultaneously then the probability of getting no heads is A/B then (A+B)² is equal to ​

Answer 1

(A+B)² is equal to 4²=16

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Answer 2

Given: Two unbiased are coins tossed simultaneously

To find: (A+B)^2 where A/B is probability of getting no heads

Explanation: When two coins are tossed simultaneously, 4 outcomes are possible.

1. Head on first coin,head on second coin
2. Head on first coin, tail on second coin
3. Tail on first coin, head on second coin
4. Tail on first coin, tail on second coin

Here, there is only one case where there is no heads on either coin.

Therefore, probability of getting no heads= 1/4

A/B= 1/4 => A=1 and B= 4

(A+B)^2= (1+4)^2= 25

Therefore, value of (A+B)^2 is 25.