Question

Two unbiased dice are rolled once. Find the probability of getting (i) a doublet (ii) the product as a prime number (iii) the sum as a prime number (iv) the sum as 1​

Answer 1

Answer:

Step-by-step explanation:

i)P(getting a doublet)=6/36=1/6

ii) P(getting product as prime no.)=4/36=1/9

iii)P(getting Dumas prime no.)=9/36=1/4

iv)p (getting sum as 1)=0