Two unbiased dice are rolled once. Find the probability of getting
(i) a doublet (equal numbers on both dice)
(ii) the product as a prime number
(iii) the sum as a prime number
(iv) the sum as 1
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Answered by
52
Answer:
Step-by-step explanation:
total outcomes = 6² = 36
i) 11,22,33,44,55,66
total=6
prob.=6/36 = 1/6
ii) 12,13,15,21,31,51,
total=6
prob=6/36=1/6
iii) 11,12,14,16,21,23,25,32,34,41,43,52,56,61,65
total=15
prob.= 15/36 = 5/12
iv) outcomes = 0
prob = 0/36 = 0
Answered by
6
Answer:
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