Question

two unbiased dice are rolled once what is the probability of getting
1.a doublet
2.a sum equal to 7​

Answer 1

The answer of both 1 and 2 is

1/6.

EXPLANATION-

If a unbaised dice is thrown then the outcomes were-

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

1. So from above we can see that total no. of outcomes are 36 and total no. of doublets {i.e. (1,1) (2,2) etc} are 6

Therefore,

probability of getting a doublet = Number of doublet/Total number of outcomes

=6/36

=6/36=1/6

2. Clearly from above we can see that the total no. outcomes having sum equal to seven=6

And total number of outcomes =36

Therefore probability of getting sum equal to 36 = no. of outcomes having sum eqaul to 7/Total number of outcomes.

=6/36

=6/36=1/6

Hope this will help you if it it helps then plz mark my answer as BRAINLIEST. And remember to always keep a smile on your face.

Answer 2

Answer:

Two unbiased dice are rolled once what is the probability of getting

1.a doublet.

2.a sum equal to 7.

ANSWER:

1. Probability of getting a doublet = 6/36 = 1/6.

2. P( a sum equal to 7) = favourable outcomes= 6

Total outcomes =36

Therefore probability is 1/6.