Question

two unbiased dice are thrown. find the probability that sum of the faces is not less than 10​

Answer 1

Answer:

SOLUTION :  

GIVEN: Two dice are thrown  

Here, two dice are thrown, so possible outcomes are :  

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6),

Hence, total number of outcomes = 36

Let E = Event of  getting the total of numbers on the dice is greater than 10

Here,the total of numbers on the dice greater than 10 are (5, 6), (6, 5) and (6, 6)

Number of outcomes favourable to E = 3

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E4) = 3/36 = 1/12

Hence, the probability of getting the total of numbers on the dice greater than 10 = 1/12 .

Answer 2

Step-by-step explanation:

10 should be also included,when probability of getting sum is not less than 10.

If probability of getting sum greater than 10 ,then we need not include 10.