Question

Two unbiased dice are thrown together .Find the probability that the sum of two outcomes is 8

Answer 1

When two dice are rolled, we get total no. of possible outcomes =(6×6)=36.

Let E = event of getting a sum of 8.

The numbers which are sum of 8 ::
E=[(2,6),(6,2),(3,5),(5,3),(4,4)]= 5

so, the probability of getting sum of 8:

P(E) =(no. of favorable events)/(total no. of possible outcomes)

P(E) = 5/36

Answer 2

Total number of outcomes/possibilities = 6 * 6 = 36

sum is 8 if the dice show up :  2+6  or 3+5 or 4+4 or 5+3 or 6+2  combinations.

so probability = 5/36