Two unequal angles of a parallelogram are in the ratio 4:5.Find all the angles of the parallelogram in degrees
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6
let the angles be 4x and 5x
we know that adjacent angles of a llgm are unequal
so 4x and 5x are adjacent angles
now we know cointerior angles are supplementary
so
4x + 5x = 180
9x = 180
x = 20
therefore
4(20) = 80
5(20)= 100
we know that opposite angles of a llgm are equal
the angles are -
80,100,80,100
we know that adjacent angles of a llgm are unequal
so 4x and 5x are adjacent angles
now we know cointerior angles are supplementary
so
4x + 5x = 180
9x = 180
x = 20
therefore
4(20) = 80
5(20)= 100
we know that opposite angles of a llgm are equal
the angles are -
80,100,80,100
Answered by
2
Hi friend, Here is the required answer:-
Let the common ratio be 'x'
So, the two unequal angles are 4x & 5x.
We know that opposite angles of a parellelogram are equal.
Therefore, all the four angles are 4x, 5x, 4x, 5x.
Now we have already studied that the sum of all angles of a quadrilateral is 360°.
Thus, 4x+5x+4x+5x=360°.
18x=360°
x=360÷18=20°. 4x=4×20°=80°,. 5x=5×20°=100°.
So the four angles of the parellelogram are:-
80°,100°,80°,100°.
Hope this helps you...
Do ask doubts if it's not clear...
Please mark as brainliest answer!!!
Let the common ratio be 'x'
So, the two unequal angles are 4x & 5x.
We know that opposite angles of a parellelogram are equal.
Therefore, all the four angles are 4x, 5x, 4x, 5x.
Now we have already studied that the sum of all angles of a quadrilateral is 360°.
Thus, 4x+5x+4x+5x=360°.
18x=360°
x=360÷18=20°. 4x=4×20°=80°,. 5x=5×20°=100°.
So the four angles of the parellelogram are:-
80°,100°,80°,100°.
Hope this helps you...
Do ask doubts if it's not clear...
Please mark as brainliest answer!!!
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