Two unknown resistance X and Y are connected to left and right gaps of a meter bridge and the balancing point is obtained at 80 cm from left. When a 10 ohm resistance is connected in parallel to X the balance point is 50 cm from the left. The values of X and Y respectively are?
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The value of x = 30 Ω and y = 7.5 v respectively.
Explanation:
- By Wheatstone's principle:
x/y = l / 100 - l
Now put l = 80
x/y = 80 / 100 - 80 = 80 / 20 = 4 -----(1)
R(eq) / y = 50 / 100 - 50 => 10x / (10 + x) 1/y = 1 ------(2)
10x / (10 + x) x 4/x = 1
40 x = 10x + x^2
40 = 10 + x x = 30 Ω
y = x/4 = 30 / 4 = 15 / 2 = 7.5 Ω
Hence the value of x = 30 Ω and y = 7.5 v respectively.
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