Math, asked by adrikasingh235, 1 year ago

Two varieties of sugar are mixed in the ratio 3:2 and sold for rs.60 per kg by making a profit of 25%. if the cost of the first variety of sugar is rs.40 per kg the cost of other variety of sugar select one:

a. rs.60

b. rs.80

c. rs.70

d. rs.100

Answers

Answered by Anonymous
5
120-20=100
d correct option
Answered by parmesanchilliwack
3

Answer:

a. rs. 60

Step-by-step explanation:

Given,

The selling price of the resultant sugar = 60 per kg,

Profit percentage = 25 %,

Thus, 125 % of the cost price of the resultant mixture = 60

⇒ The cost price of the resultant mixture = \frac{60\times 100}{125}

=\frac{6000}{125}

=48\text{ per kg}

Since, the first variety of sugar is rs. 40 per kg,

Let x be the price of second variety of sugar,

And, they are mixed in the ratio 3:2,

Then,

\frac{x-48}{48-40}=\frac{3}{2}

2x-96=24

2x=120\implies x = 60

Hence, the price of other variety of sugar is 60 per kg.

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