Question

two vector have magnitude 6 units and 8 units respectively. Find magnitude of resultant of two vectors if angle between two vectors is 0°​

Answer 1

Answer:

10 units

Explanation:

Resultant(R) of two vectors is given as

R = sq root[ (R1)^2 + (R)^2 + 2*R1*R2*cos(a) ]

where R1 = magnitude of first vector

R2 = magnitude of second vector

a = angle between two vectors

Now, R1 = 6 units, R2 = 8units, R = 10 units

substituting the values, we get

10= sq root[ (6)^2 + (8)^2 + 2*6*8*cos(a) ]

or (10)^2 = [ 36 + 64 + 96cos(a) ]

100 = 100 + 24cos (a)

0 = 24cos(a)

cos(a) = 0 -----ok

so magnitude of resultant of two vector = [(6^2 + 8^2)]^0.5 = 10 units