Physics, asked by jay96339, 9 months ago

two vectors a and b are equal in magnitude but perpendicular to each other assuming a suitable scale represent their following combination a+2b, a-2b, 2a-b, b-1/2a​

Answers

Answered by rashich1219
5

Given:

Two vectors a and b are equal in magnitude but perpendicular to each other.

To Find:

Assuming a suitable scale represent their following combination a+2b, a-2b, 2a-b, b-1/2a​?

Solution:

it is given that , two vectors a and b are equal in magnitude but perpendicular

to each other.

therefore, a =  b and θ = 90 degree :angle between a and b.

so, according to question, we have

for, a+2b;

r = \sqrt{a^2+(2b)^2+4abcos(\pi/2)}\\\\r=\sqrt{a^2+(2a)^2+4ab\times0}\\\\r=\sqrt{5}a \ or \ \sqrt{5}b

for, a-2b

r=\sqrt{5} \ a \ or \ \sqrt{5}b

for , 2a-b

r=\sqrt{5} \ a \ or \ \sqrt{5}b

for, b-(1/2)a

r=\sqrt{3/2}a \ or \ \sqrt{3/2} b

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