two vectors A1 and A2 each of magnitude are inclined to each other such that their resultant is equal to √3Afind the resultant of vectorA1 1 and -A1
vector
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Here i m not clear if you are asking about the resultant of - A1 and A1 cause it will be zero but if it is A1 and A2 then we need calculate the magnitude and directions in terms of A
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The resultant of vector A1 and -A1 is 0.
The magnitude both the vectors A1 and A2 is equal to A .
|A1| = A , |A2| = A
resultant of A1 and A2 = √3 A
=> √3 A = √(A² + A² + 2A² cos x)
=> 3A² = 2A² + 2A² cos x
=> 1/2 = cos x
x = 60°
The angle between A1 and A2 is equal to 60° .
Now , we have to find the resultant of A1 and -A1. The angle between these vectors = 180°
resultant of A1 and -A1 = √(A²+A²+2A² cos 180° )
=> √(2A²-2A²)
=> 0
The resultant of A1 and -A1 will be zero as they are equal in magnitude but opposite in direction.
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