Question

two vectors are given by a= -2i+j -3k and b = 5i+3j-2k. If 3a+2b-c=0 then third vector c is​

Answer 1

Answer:

3a + 2b - c = 0

So, according to the question

⇒ 3 (- 2i + j - 3k) + 2 (5i + 3j - 2k) - c = 0

⇒ - 6i + 3j - 9k + 10i + 6j - 4k = c

⇒ c = 4i + 9j - 13k

Hence, c = 4i + 9j - 13k.

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