two vectors are given bya^=-2i^+j^-3k^and b^=5i^+3j^-2k^.if 3a^+2b^-c^=0 then third vector is
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Step-by-step explanation:
a = -2i+j-3k
b = 5i+3j-2k
3a+2b-c= 0
3a+2b=c
Substitute a and b values
c= 3(-2i+j-3k )+2(5i+3j-2k)
c= -6i+3j-9k+10i+6j-4k
c= 4i+9j-13k
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