Two vectors of equal magnitude 5 unit have an angle 60° between them. Find the magnitude of the difference of the vectors.
Answers
Answered by
124
Let 5he vectors be a and b.
|a - b|² = (a - b). (a - b)
= |a|² + |b|² - 2a.b (noting that a.b = b.a))
= 25 + 25 - 2 x 5 x 5 cos60°
= 50 - 50 x (1/2) = 25.
So |a - b| = 5.
|a - b|² = (a - b). (a - b)
= |a|² + |b|² - 2a.b (noting that a.b = b.a))
= 25 + 25 - 2 x 5 x 5 cos60°
= 50 - 50 x (1/2) = 25.
So |a - b| = 5.
Answered by
24
Answer:
See the pic for your answer
Attachments:
Similar questions