Two vectors of magnitude 5 unit each have an angle 60 between them. The magnitudes of the sum of
the vectors and the difference of the vectors respectively are
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Answer:
Explanation:
ure shows the construction of the sum
A→+B→ and the differece A→−B→.
aA→+B→ is the sum to A→andB→. Both have a magnitude of unit nd the angle between them is 600. Thus, the magnitude of the sum is
∣∣∣A→+B→∣∣∣=52+52+2×5x5cos600−−−−−−−−−−−−−−−−−−−√
=2×5cos300=53–√ unit.
b. A→−B→ is the sum of A→and(−B→). As shown in the ure, angle between A→and(−B→) is 1200. The magnitude of both A→and(−B→) is 5 unit so,
∣∣∣A→−B→∣∣∣=95−−√2+52+2x5×5cos1200)
1 = 2xx cos6060 = 5 unit`.
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