two vectors P = 2 i + aj - K and 3i - j - K are perpendicular to each other find the value of a
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Answered by
1
5
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As the 2 vectors are perpendicular,
Their dot product is zero.
So,
(2i+aj-k).(3i-j-k)=0
So,
6-a+1=0
Therefore,
a=7
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