Math, asked by jahid5280, 11 months ago

Two vehicles a and b leave from y to x. A overtakes b at 10:30 am and reaches x at 12:00. It waits for two hours and returns to y. On its way, it meets b at 3 pm and reaches y at 5 pm. B reaches city x waits for 1 hour and returns to y after how many hours will b reach to y from the time a overtook him.

Answers

Answered by amitnrw
0

Answer:

3.5 hrs

Step-by-step explanation:

Two vehicles a and b leave from y to x. A overtakes b at 10:30 am and reaches x at 12:00. It waits for two hours and returns to y. On its way, it meets b at 3 pm and reaches y at 5 pm. B reaches city x waits for 1 hour and returns to y after how many hours will b reach to y from the time a overtook him.

Let say Speed of A  =  a  km/hr

Speed of B = b km/hr

Distance travelled = 1.5a

after 2hr a start at 2:00 PM & meet b at 3PM

=> Distance traveled by a = 1 a

Total Distance travelled = 2.5a

b has run for 10:30 to 3 pm with 1 hr wait = 3.5b

2.5a = 3.5b

2.5a/b = 3.5b/b = 3.5 hrs

Similar questions