Two vehicles a and b leave from y to x. A overtakes b at 10:30 am and reaches x at 12:00. It waits for two hours and returns to y. On its way, it meets b at 3 pm and reaches y at 5 pm. B reaches city x waits for 1 hour and returns to y after how many hours will b reach to y from the time a overtook him.
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Answer:
3.5 hrs
Step-by-step explanation:
Two vehicles a and b leave from y to x. A overtakes b at 10:30 am and reaches x at 12:00. It waits for two hours and returns to y. On its way, it meets b at 3 pm and reaches y at 5 pm. B reaches city x waits for 1 hour and returns to y after how many hours will b reach to y from the time a overtook him.
Let say Speed of A = a km/hr
Speed of B = b km/hr
Distance travelled = 1.5a
after 2hr a start at 2:00 PM & meet b at 3PM
=> Distance traveled by a = 1 a
Total Distance travelled = 2.5a
b has run for 10:30 to 3 pm with 1 hr wait = 3.5b
2.5a = 3.5b
2.5a/b = 3.5b/b = 3.5 hrs
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