Two vertical poles of heights “a” m and “b” m stand apart on a horizontal plane. The height (in meters) of the point of intersection of the lines joining the top of each pole to the foot of the other from this horizontal plane is
Answers
The height of the point of intersection of the lines joining the top of each pole to the foot of the other from this horizontal plane is given below:
Explanation:
Let,
xz = m
yz = n
xy = d
PZ = y
PZ ║ Poles
Hence,
m/d = y/b ......(1)
n/d = y/a ......(2)
Adding both
=> m/d + n/d = y/b + y/a
=> (m + n)/d = y (a + b)/ab
=> d/d = y (a + b)/ab
=> 1 = y (a + b)/ab
=> y = ab/(a + b)
Therefore, the height of the point of intersection of the lines joining the top of each pole to the foot of the other from this horizontal plane is ab/(a + b).
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